Question

What voltage is involved in a 1.44-kW short circuit through a 0.100-Ω resistance?

a. 120 V
b. 240 V
c. 180 V
d. 360 V

Answer 1

The voltage involved in the short circuit is 12V.

Step-by-step explanation:

The voltage involved in a 1.44-kW short circuit through a 0.100-Ω resistance can be calculated using Ohm's Law. Ohm's Law states that voltage(V) is equal to the current(I) multiplied by the resistance(R).

V = I * R

Given that the power(P) is 1.44 kW and the resistance(R) is 0.100 Ω, we can rearrange Ohm's Law to solve for voltage(V).

V = √(P * R)

V = √(1.44 * 1000 * 0.100)

V = √144

V = 12V

Therefore, the voltage involved in the short circuit is 12V.