Question

A cauterizer, used to stop bleeding in surgery, puts out 2.00 mA at 15.0 kV. What is its power output?

a. 30.0 W
b. 0.030 W
c. 15.0 W
d. 0.002 W

Answer 1

The power output of a cauterizer with an output of 2.00 mA at 15.0 kV is 30.0 Watts (W). The resistance of the path can be calculated using Ohm's law and equals 7,500,000 ohms (or 7.5 MΩ).

Step-by-step explanation:

The power output of a cauterizer that puts out 2.00 mA at 15.0 kV can be calculated using the formula

Power (P) = Voltage (V) × Current (I).

Given the values, the calculation is:

P = 15,000 volts × 0.002 amps = 30.0 Watts (W)

Now, to calculate the resistance of the path, we can use Ohm's law, which is Resistance (R) = Voltage (V) / Current (I):

R = 15,000 volts / 0.002 amps = 7,500,000 ohms (or 7.5 MΩ)