Question

How much power is dissipated in a short circuit of 220-V AC through a resistance of 0.250Ω? (b) What current flows?

a. (a) 19,360 W (b) 440 A
b. (a) 10,890 W (b) 220 A
c. (a) 12,100 W (b) 330 A
d. (a) 8,800 W (b) 180 A

Answer 1

Using the formulas for power (P = V^2 / R) and current (I = V / R), the power dissipated in a short circuit through a 0.250Ω resistance with a 220-V AC source is calculated to be 193,600 W, and the current flow would be 880 A. However, these values are not present in the given options, suggesting an issue with the question.(option a)

Step-by-step explanation:

When dealing with electric circuits, it is essential to understand how power is dissipated. In this case, we are dealing with a short circuit, where the resistance is very low, and the potential for power dissipation is high. To calculate the power dissipated in a resistance of 0.250Ω with a 220-V AC source, we use the formula P = V^2 / R. Plugging in the values, we get:

P = (220^2) / 0.250 = 193,600 W or 19.36 kW.

For the current flow, we use Ohm's Law I = V / R. The corresponding calculation would be:

I = 220 / 0.250 = 880 A.

However, the options provided do not match this answer, so we need to consider that this might be a trick question, or there is a mistake in the question itself. Always verify your calculations and the question before making a conclusion.

Hence, the answer is option a