Question

Calculate the effective resistance of a pocket calculator that has a 1.35-V battery and through which 0.200 mA flows.

a) 6.75 kΩ
b) 675 Ω
c) 67.5 Ω
d) 13.5 kΩ

Answer 1

The effective resistance of a pocket calculator with a 1.35-V battery and a current flow of 0.200 mA is calculated using Ohm's law, resulting in a resistance of 6.75 kΩ. Option a is the correct answer.

Step-by-step explanation:

In order to calculate the effective resistance of a pocket calculator, we can use Ohm's Law, which states that resistance is equal to voltage divided by current.

First, we need to convert the current from milliamperes to amperes by dividing it by 1000. So, 0.200 mA is equal to 0.0002 A.

Next, we can apply Ohm's Law:

R = V / I

R = 1.35 V / 0.0002 A = 6750 Ω.

Therefore, the effective resistance of the pocket calculator is 6750 Ω, which corresponds to option a).