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What current flows through the glass insulator with a resistance of 1.00×10^9 Ω if the voltage is 200 kV?

a. 2.00 A
b. 0.20 A
c. 1.00 × 10^-7 A
d. 2.00 × 10^-7 A

User Phastasm
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1 Answer

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Final answer:

By applying Ohm's law (I = V/R), we find that the current flowing through a glass insulator of resistance 1.00×10^9 Ω with a voltage of 200 kV is 2.00×10^-7 A.

Step-by-step explanation:

To calculate the current that flows through a glass insulator in a high-voltage power transmission line, we can use Ohm's law. Ohm's law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points, and inversely proportional to the resistance (R) of the conductor. The formula is given by I = V/R.

In this instance, the resistance of the glass insulator is given as 1.00×109 Ω, and the voltage is 200 kV (or 200,000 volts). By applying Ohm's law, we can find the current:

I = V/R = 200,000 V / 1.00×109 Ω = 2.00×10-7 A

Therefore, the current that flows through the insulator is 2.00×10-7 amperes.

User BlackTigerX
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