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Given:

P₄()+5O₂()⟶P₄O₁₀() ΔG°=−2697.0 kJ/mol

2H₂()+O₂()⟶2H₂O() ΔG°=−457.18 kJ/mol

6H₂O()+P₄O₁₀()⟶4H₃PO₄() ΔG°=−428.66 kJ/mol

(a) Determine the standard free energy of formation, Δ∘f, for phosphoric acid.

(b) How does your calculated result compare to the value in Appendix G? Explain.

User Typos
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Final answer:

The standard free energy of formation, Δ∘f, for phosphoric acid is -1828.72 kJ/mol. The calculated value can be compared to the value in Appendix G to assess the accuracy of the calculation.

Step-by-step explanation:

The standard free energy of formation, Δ∘f, for phosphoric acid (H3PO4) can be determined by using the standard free energy values given in the equations provided. The balanced equation for the formation of phosphoric acid is:

6H₂O(g) + P₄O₁₀(s) ⟶ 4H₃PO₄(l)

From the given data, the standard free energies for the reactions are:

ΔG° for P₄()+5O₂()⟶P₄O₁₀() = -2697.0 kJ/mol

ΔG° for 2H₂()+O₂()⟶2H₂O() = -457.18 kJ/mol

ΔG° for 6H₂O()+P₄O₁₀()⟶4H₃PO₄() = -428.66 kJ/mol

Using Hess's Law, we can add the free energies of the reactions to obtain the total standard free energy change for the formation of phosphoric acid:

ΔG° for 4H₃PO₄(l) formation = (4 x ΔG° for 2H₂()+O₂()) + (ΔG° for P₄()+5O₂()) - (ΔG° for 6H₂O()+P₄O₁₀())

= (4 x -457.18 kJ/mol) + (-2697.0 kJ/mol) - (-428.66 kJ/mol)

= -1828.72 kJ/mol

Therefore, the standard free energy of formation, Δ∘f, for phosphoric acid is -1828.72 kJ/mol.

(b) The calculated standard free energy of formation for phosphoric acid can be compared to the value in Appendix G to determine the accuracy of the calculation. The value obtained (-1828.72 kJ/mol) can be compared to the value in Appendix G to assess the accuracy of the calculation.

User Jim Rubenstein
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