Final answer:
The drift velocity in a copper wire of twice the diameter and carrying 20.0 A is four times the original.
Step-by-step explanation:
To find the drift velocity in a copper wire of twice the diameter and carrying 20.0 A, we can use the equation I = nqAvd.
Since the diameter is twice the original, the area of the cross-section will be four times the original.
The current remains the same, so we can calculate the new drift velocity:
vd' = vd * (A' / A)
where A' is the area of the new wire and A is the area of the original wire.
Since A' = 4A, the new drift velocity will be four times the original (option b).