Final answer:
To prepare a 3.08 m aqueous solution of glycerin, dissolve a specific mass of glycerin in a specific mass of water. The freezing point depression can be determined using the equation ΔTf = Kf × m.
Step-by-step explanation:
To prepare a 3.08 m aqueous solution of glycerin, you would dissolve a specific mass of glycerin in a specific mass of water. The freezing point of the solution can be determined using the equation ΔTf = Kf × m, where ΔTf is the freezing point depression, Kf is the molal freezing point depression constant, and m is the molality of the solution.
In this case, we have four options:
- a) Dissolve 100 g of glycerin in 200 g of water; -2.10 °C
- b) Dissolve 120 g of glycerin in 250 g of water; -3.67 °C
- c) Dissolve 150 g of glycerin in 350 g of water; -5.36 °C
- d) Dissolve 180 g of glycerin in 500 g of water; -7.14 °C
We can calculate the freezing point depression for each option and compare it to the given freezing point depressions to find the correct answer.
The correct answer is option b, where dissolving 120 g of glycerin in 250 g of water results in a freezing point depression of -3.67 °C.