Final answer:
NaOH(aq) and HCl(aq) are strong electrolytes with high conductivity due to their complete dissociation into ions. C₆H₁₂O₆(aq) is a nonelectrolyte with low conductivity as it does not form ions. NH₃(aq) is a weak electrolyte with moderate conductivity.
Step-by-step explanation:
The expected electrical conductivity of solutions depends on the presence and mobility of ions in the solution. Strong electrolytes tend to dissociate completely in water, yielding a high number of ions and thus high conductivity.
NaOH(aq) is a strong base that dissociates completely into Na+ and OH- ions, thus it is an excellent conductor of electricity.
HCl(aq) is a strong acid that also dissociates completely into H+ and Cl- ions, making it another excellent conductor of electricity.
C₆H₁₂O₆(aq) (glucose) does not dissociate into ions; it remains as intact glucose molecules in solution, making it a nonelectrolyte with very low electrical conductivity.
NH₃(aq), ammonia in water, forms a small amount of NH4+ and OH- ions, classifying it as a weak electrolyte with comparatively lower conductivity than strong acids or bases.