Question

What current flows through the bulb of a 3.00-V flashlight when its hot resistance is 3.60 Ω?

a) 0.83 A
b) 0.60 A
c) 0.50 A
d) 0.33 A

Answer 1

The current flowing through the bulb of a 3.00-V flashlight with a hot resistance of 3.60 Ω is calculated using Ohm's Law, resulting in 0.83 A.

Step-by-step explanation:

To calculate the current that flows through the bulb of a 3.00-V flashlight with a hot resistance of 3.60 Ω, we use Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). Using the provided values, the current I = V / R = 3.00 V / 3.60 Ω.

The calculation yields a current of 0.8333... A, which when rounded to two significant digits, as is customary in physics, gives a result of 0.83 A. Therefore, the correct answer to the question, "What current flows through the bulb of a 3.00-V flashlight when its hot resistance is 3.60 Ω?", is option a) 0.83 A.

The current flowing through the bulb of a 3.00-V flashlight can be calculated using Ohm's Law, which states that current is equal to voltage divided by resistance. In this case, the voltage is 3.00 V and the resistance is 3.60 Ω. So the current is 3.00 V ÷ 3.60 Ω = 0.83 A. Therefore, the correct answer is a) 0.83 A.