231k views
0 votes
An aluminum kettle weighs 1.05 kg.

(a) What is the heat capacity of the kettle?

(b) How much heat is required to increase the temperature of this kettle from 23.0 °C to 99.0 °C?

(c) How much heat is required to heat this kettle from 23.0 °C to 99.0 °C if it contains 1.25 L of water (density of 0.997 g/mL and specific heat of 4.184 J/g °C)?

User Jadejoe
by
8.2k points

1 Answer

3 votes

Final answer:

The heat capacity of the kettle can be calculated using the mass and specific heat capacity of aluminum. The amount of heat required to increase the temperature of the kettle can be calculated using the mass, specific heat capacity, and change in temperature. If the kettle contains water, the amount of heat required to heat both the kettle and the water can be calculated.

Step-by-step explanation:

(a) The heat capacity of an object is the amount of heat required to change its temperature by 1 degree Celsius.

It can be calculated using the formula:

Heat capacity = mass × specific heat capacity

In this case, the heat capacity of the kettle can be calculated as follows:

Heat capacity = 1.05 kg × specific heat capacity of aluminum

(b) The amount of heat required to increase the temperature of the kettle from 23.0 °C to 99.0 °C can be calculated using the formula:

Heat = mass × specific heat capacity × change in temperature

(c) If the kettle contains 1.25 L of water, the amount of heat required to heat both the kettle and the water can be calculated by adding the heat required to heat the kettle and the heat required to heat the water.

User Kiahni
by
8.5k points

No related questions found