Final answer:
the mass of oxygen in the cylinder is approximately 3.87 g
To solve for the mass of oxygen in the cylinder, we can use the ideal gas law and the molar mass of oxygen.
Step-by-step explanation:
To solve this problem, we can use the ideal gas law:
PV = nRT
where
P is the pressure
V is the volume
n is the number of moles
R is the ideal gas constant
T is the temperature
We can rearrange the equation to solve for the number of moles:
n = PV / RT
Plugging in the given values:
n = (10.0 atm)(3.00 L) / (0.0821 L·atm/mol·K)(28.0 °C + 273.15)
n = 0.121 mol
To calculate the mass, we can use the molar mass of oxygen, which is 32 g/mol.
mass = n * molar mass
mass = 0.121 mol * 32 g/mol
mass = 3.87 g
Therefore, the mass of oxygen in the cylinder is approximately 3.87 g.