Final answer:
To determine the pressure of the gas in the sample, subtract the height of the mercury column in the open-end manometer from the atmospheric pressure at sea level. The pressure of the gas is equal to the atmospheric pressure in options a) and d). The pressure of the gas in option b) would be the atmospheric pressure minus the height of the mercury column.
Step-by-step explanation:
The pressure of the gas in the sample can be determined by subtracting the height of the mercury column in the open-end manometer from the atmospheric pressure at sea level. Since the atmospheric pressure is 760.0 mm Hg, the pressure of the gas in the sample in a) 760.0 mm Hg would be 760.0 mm Hg - 0 mm Hg = 760.0 mm Hg. Similarly, the pressure of the gas in the sample in b) 380.0 mm Hg would be 760.0 mm Hg - 380.0 mm Hg = 380.0 mm Hg.
In c) 1520 mm Hg, the pressure of the gas in the sample cannot be higher than the atmospheric pressure. Therefore, the pressure of the gas would still be 760.0 mm Hg.
In d) 0 mm Hg, the pressure of the gas in the sample would be 760.0 mm Hg - 0 mm Hg = 760.0 mm Hg. The pressure of the gas cannot be lower than the atmospheric pressure at sea level.