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How many grams of gas are present in each of the following cases?

a) 10.5 moles of CH4
b) 2.25 moles of O2
c) 0.75 moles of CO2
d) 5.2 moles of N2

User Augustina
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1 Answer

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Final answer:

a) There are 168.53 grams of CH4 in 10.5 moles. b) There are 72.00 grams of O2 in 2.25 moles. c) There are 33.01 grams of CO2 in 0.75 moles. d) There are 145.45 grams of N2 in 5.2 moles.

Step-by-step explanation:

a) To find the grams of CH4, we first need to determine the molar mass of CH4. The molar mass of carbon (C) is 12.01 g/mol, and the molar mass of hydrogen (H) is 1.01 g/mol. Since CH4 has one carbon atom and four hydrogen atoms, the molar mass of CH4 is (12.01 g/mol) + (4 * 1.01 g/mol) = 16.05 g/mol. To calculate the grams of CH4, we use the formula:

Grams = Moles * Molar Mass

Grams of CH4 = 10.5 mol * 16.05 g/mol = 168.53 g

Therefore, there are 168.53 grams of CH4 in 10.5 moles.

b) Following a similar process, we find that the molar mass of O2 is (2 * 16.00 g/mol) = 32.00 g/mol. To calculate the grams of O2, we use the formula:

Grams of O2 = 2.25 mol * 32.00 g/mol = 72.00 g

Therefore, there are 72.00 grams of O2 in 2.25 moles.

c) The molar mass of CO2 is (12.01 g/mol) + (2 * 16.00 g/mol) = 44.01 g/mol. To calculate the grams of CO2, we use the formula:

Grams of CO2 = 0.75 mol * 44.01 g/mol = 33.01 g

Therefore, there are 33.01 grams of CO2 in 0.75 moles.

d) The molar mass of N2 is (2 * 14.01 g/mol) = 28.02 g/mol. To calculate the grams of N2, we use the formula:

Grams of N2 = 5.2 mol * 28.02 g/mol = 145.45 g

Therefore, there are 145.45 grams of N2 in 5.2 moles.

User DiMono
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