Question

Gallium chloride is formed by the reaction of 2.6 L of a 1.44 M solution of HCl according to the following equation: 2Ga+6HCl⟶2GaCl3+3H2.

What is the molarity of the gallium chloride (GaCl3) solution produced in this reaction?
a) 0.48 M
b) 0.72 M
c) 1.44 M
d) 2.88 M

Answer 1

The molarity of the gallium chloride solution produced is 0.48 M after calculating the moles of HCl used, converting that to moles of GaCl3 according to the stoichiometry of the balanced reaction, and finally dividing by the original volume of the solution. The correct option is A.

Step-by-step explanation:

To calculate the molarity of the gallium chloride solution produced, start by using the given molarity of HCl to find the number of moles of HCl that reacted:

1. Determine the moles of HCl used: moles HCl = volume (L) × molarity (M). For 2.6 L of 1.44 M HCl, this is 2.6 L × 1.44 M = 3.744 moles of HCl.
2. From the balanced equation, 6 moles of HCl produce 2 moles of GaCl3; therefore, calculate the moles of GaCl3 formed: moles GaCl3 = moles HCl ÷ (2 moles GaCl3 / 6 moles HCl) = 3.744 moles ÷ 3 = 1.248 moles of GaCl3.
3. Using the volume of the solution, calculate the molarity of the produced GaCl3 solution: molarity = moles of solute / volume of solution (L). Thus, molarity of GaCl3 = 1.248 moles / 2.6 L = 0.48 M.

Hence, the molarity of the gallium chloride solution produced is 0.48 M.