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How many molecules of the sweetener saccharin can be prepared from 30 C atoms, 25 H atoms, 12 O atoms, 8 S atoms, and 14 N atoms?

a) 1.25 x 10¹⁹ molecules
b) 2.50 x 10¹⁹ molecules
c) 5.00 x 10¹⁹ molecules
d) 1.00 x 10²⁰ molecules

User QuinRiva
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1 Answer

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Final answer:

The sweetener saccharin can be prepared from 8 S atoms, resulting in 1.25 x 10¹⁹ molecules of saccharin.

Step-by-step explanation:

The molecular formula for saccharin is C7H5NO3S. To determine the number of saccharin molecules that can be prepared, we need to find the limiting reactant, which is the atom with the fewest number of atoms in our starting materials. In this case, we have 30 C atoms, 25 H atoms, 12 O atoms, 8 S atoms, and 14 N atoms.

From the molecular formula, we can see that the limiting reactant is S since we only have 8 S atoms. The ratio of S atoms to saccharin molecules is 1:1, so we can prepare 8 molecules of saccharin from the 8 S atoms. Therefore, the correct answer is a) 1.25 x 10¹⁹ molecules.

User Gregnr
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