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What is the potential (0.530 X 10^10) m from a proton (the average distance between the proton and electron in a hydrogen atom)?

A) (2.27 X 10^9V)
B) (8.99 X 10^8V)
C) (4.49 X 10^8V)
D) (1.13 X 10^9V)

User Crismogram
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1 Answer

2 votes

Final answer:

Using the formula V = (k * q) / r, the potential at the average distance between a proton and electron in a hydrogen atom is calculated to be 2.71 × 10^1 V, which does not match any of the provided options.

Step-by-step explanation:

To find the potential at a distance of 0.530 × 10^-10 m from a proton (which is the average distance between the proton and electron in a hydrogen atom), we will use the formula for the electric potential due to a point charge, V = (k * q) / r, where V is the potential, k is Coulomb’s constant (8.99 × 10^9 N · m^2/C^2), q is the charge of the proton (1.60 × 10^-19 C), and r is the distance from the charge.

Plugging in the values, we have V = ((8.99 × 10^9) × (1.60 × 10^-19)) / (0.530 × 10^-10) = (1.4384 × 10^-9) / (0.530 × 10^-10) = 2.71 × 10^1 V.

Since this result is not in the given options, it appears there is a mistake in the calculation or in the options provided by the question.

User Moshe Kravchik
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8.0k points