Question

Half-reaction method:

Balance the given equation in acidic conditions: Zn(s) + NO3⁻(aq) → Zn²+(aq) + N₂O(g)
A) Zn(s) + 2NO3⁻(aq) → Zn²+(aq) + N₂O(g) + 2H₂O(l)
B) 3Zn(s) + 2NO3⁻(aq) → 3Zn²+(aq) + N₂O(g) + 2H₂O(l)
C) Zn(s) + 2NO3⁻(aq) → Zn²+(aq) + N₂O(g) + H₂O(l)
D) 2Zn(s) + 2NO3⁻(aq) → 2Zn²+(aq) + N₂O(g) + 2H₂O(l)

Answer 1

The balanced equation for the given reaction in acidic conditions is: Zn(s) + 2NO3⁻(aq) → Zn²+(aq) + N₂O(g) + 2H₂O(l).

Step-by-step explanation:

The balanced equation for the given reaction in acidic conditions is:

Zn(s) + 2NO3⁻(aq) → Zn²+(aq) + N₂O(g) + 2H₂O(l)

The oxidation half-reaction is: Zn(s) → Zn²+(aq) + 2e⁻ and the reduction half-reaction is: 2NO3⁻(aq) + 4H⁺(aq) + 2e⁻ → N₂O(g) + 2H₂O(l).

By balancing the number of atoms and charges in both half-reactions, we can obtain the balanced equation.