Final answer:
The magnitude of the force exerted on a 3.50 μC charge by a 250 N/C electric field that points due east is (8.75 × 10³ N) eastward.
Step-by-step explanation:
The magnitude of the force exerted on a charge can be calculated using the formula:
F = qE
Where F is the force, q is the charge, and E is the electric field strength.
In this case, the charge is 3.50 μC and the electric field strength is 250 N/C. Substituting these values into the formula:
F = (3.50 × 10-6 C)(250 N/C)
F = 8.75 × 10-4 N.
The force is directed in the same direction as the electric field, which is due east. Therefore, the magnitude and direction of the force exerted on the charge is (8.75 × 10³ N) eastward.