Question

The naturally occurring electric field on the ground to an open sky point (3.00 m) above is (1.13 X 10^2 N/C). Calculate the electric potential at this height.

A) (339 V)
B) (3390 V)
C) (113 V)
D) (1130 V)

Answer 1

The electric potential at a height of 3.00 m is 339 V.

Step-by-step explanation:

The electric potential at a height of 3.00 m is equal to the product of the electric field and the height. To calculate the electric potential, multiply the electric field (1.13 x 10^2 N/C) by the height (3.00 m).

Electric potential = (Electric field) x (Height)

Electric potential = (1.13 x 10^2 N/C) x (3.00 m) = 339 V