Question

What capacitance is needed to store (3.00 , mu C) of charge at a voltage of (120 , V)?

a) (0.025 , mu F)
b) (250 , mu F)
c) (25 , mu F)
d) (0.0025 , mu F)

Answer 1

The capacitance needed to store 3.00 µC of charge at a voltage of 120 V is 0.025 µF.

Step-by-step explanation:

To calculate the capacitance needed to store a certain amount of charge at a given voltage, we can use the formula:
C = Q / V
Where:
C is the capacitance measured in Farads (F)
Q is the charge measured in Coulombs (C)
V is the voltage measured in Volts (V)

Plugging in the values given in the question:
C = (3.00 µC) / (120 V) = 0.025 µF

Therefore, the correct answer is (a) 0.025 µF.