Question

How many molecules of C₂H₄Cl₂ can be prepared from 15 C₂H₄ molecules and 8 Cl₂ molecules?

a) 120 molecules
b) 240 molecules
c) 360 molecules
d) 480 molecules

Answer 1

The number of molecules of C₂H₄Cl₂ that can be prepared from 15 C₂H₄ molecules and 8 Cl₂ molecules is 15 molecules.

Step-by-step explanation:

To determine how many molecules of C₂H₄Cl₂ can be prepared, we need to find the limiting reactant.

First, we calculate the number of molecules for each reactant:

C₂H₄: 15 molecules

Cl₂: 8 molecules

Next, we need to find the mole ratio between C₂H₄ and C₂H₄Cl₂:

C₂H₄ + Cl₂ → C₂H₄Cl₂

From the balanced equation, we can see that for every 1 molecule of C₂H₄, we produce 1 molecule of C₂H₄Cl₂.

Since we have 15 C₂H₄ molecules, we can produce 15 C₂H₄Cl₂ molecules.

Therefore, the answer is 15 molecules (option a).