Question

Copper(II) sulfide is oxidized by molecular oxygen to produce gaseous sulfur trioxide and solid copper(II) oxide. The gaseous product then reacts with liquid water to produce liquid dihydrogen sulfate as the only product. Write the two equations that represent these reactions.

a) 2CuS(s) + 3O₂(g) → 2CuO(s) + 2SO₃(g)
b) SO₃(g) + H₂O(l) → H₂SO₄(l)
c) 2CuS(s) + O₂(g) → 2CuO(s) + SO₃(g)
d) CuS(s) + O₂(g) → CuO(s) + SO₃(g), SO₃(g) + H₂O(l) → H₂SO₄(l)

Answer 1

The equations that represent the reactions are: 2CuS(s) + 3O₂(g) → 2CuO(s) + 2SO₃(g), SO₃(g) + H₂O(l) → H₂SO₄(l)

Step-by-step explanation:

The two equations that represent the reactions described are:
a) 2CuS(s) + 3O₂(g) → 2CuO(s) + 2SO₃(g)
b) SO₃(g) + H₂O(l) → H₂SO₄(l)

In the first reaction, copper(II) sulfide (CuS) is oxidized by molecular oxygen (O₂) to produce solid copper(II) oxide (CuO) and gaseous sulfur trioxide (SO₃). In the second reaction, sulfur trioxide reacts with liquid water (H₂O) to produce liquid dihydrogen sulfate (H₂SO₄) as the only product.