Final answer:
The voltage across an 8.00 nm-thick membrane with an electric field of 5.50 MV/m can be calculated using the formula V = E x d. After converting the thickness to meters and doing the calculation, the voltage is found to be 44 volts.
Step-by-step explanation:
The question is asking to calculate the voltage across a cell membrane, given the electric field strength and the thickness of the membrane. The electric field strength is given as 5.50 MV/m, and the thickness of the membrane is 8.00 nm. Voltage (V) can be found by the formula V = E × d, where E is the electric field and d is the distance (thickness).
First, convert the thickness into meters: 8.00 nm = 8.00 × 10-9 m. Then, multiply the electric field strength by the thickness to find the voltage:
V = 5.50 × 106 V/m × 8.00 × 10-9 m = 44 V
The voltage across a membrane can be calculated using the formula V = E * d, where V is the voltage, E is the electric field strength, and d is the thickness of the membrane. In this case, the electric field strength is given as 5.50 MV/m and the thickness of the membrane is given as 8.00 nm (which can be converted to meters by dividing by 10^9). Plugging in these values, we get V = (5.50 * 10^6 V/m) * (8.00 * 10^(-9) m) = 4.40 V. Therefore, the correct answer is option a) (4.40 V).
Therefore, the voltage across the membrane is 44 volts (option a).