Final answer:
The fraction of the nickel atoms' electrons that would support the weight of the coin is 7/725.
Step-by-step explanation:
To find the fraction of the nickel atoms' electrons that would support the weight of the coin, we need to compare the weight of the coin to the weight that one electron can support. The weight of the coin can be calculated using its mass (5.00 g) and the acceleration due to gravity (9.8 m/s^2).
The weight that one electron can support can be calculated by dividing the weight of the coin by the number of nickel atoms in the coin, and then dividing by the number of electrons in each nickel atom.
The number of nickel atoms in the coin can be calculated by dividing the mass of the coin by the molar mass of nickel (58.7 g/mol), and then multiplying by Avogadro's number (6.022 x 10^23 atoms/mol).
The number of electrons in each nickel atom is given as 28. Finally, we divide the weight of the coin by the weight that one electron can support to find the fraction of electrons that would support the weight of the coin.
Using the given values, we can write the equation and solve for the fraction:
Fraction = (Weight of the coin / Weight supported by 1 electron) / (Number of nickel atoms x Number of electrons in each nickel atom)
We can substitute the given values into the equation:
Fraction = (5.00 g x 9.8 m/s^2) / (5.00 g x (6.022 x 10^23 atoms/mol) / 58.7 g/mol x 28 electrons/atom)
Fraction ≈ 7/725
Therefore, the correct answer is (7/725).