Final answer:
The capacitance of a parallel plate capacitor with the given specifications is approximately 3.55 x 10^-10 F. When a voltage of 9.00 V is applied to it, the charge held by the capacitor is approximately 3.20 x 10^-9 C.
Step-by-step explanation:
To calculate the capacitance of a parallel plate capacitor, we use the formula:
C = ε0 εr A / d
where C is the capacitance, ε0 is the vacuum permittivity (8.85 x 10-12 F/m), εr is the relative permittivity of neoprene rubber (typically about 6.7), A is the area of the plates (1.50 m2), and d is the separation between the plates (0.0200 mm or 0.0200 x 10-3 m).
Plugging in the values, we get:
C = (8.85 x 10-12 F/m) * 6.7 * (1.50 m2) / (0.0200 x 10-3 m)
This results in a capacitance of approximately 3.55 x 10-10 F.
For the charge held by the capacitor when a voltage of 9.00 V is applied, we use the formula:
Q = C * V
where Q is the charge, and V is the voltage applied.
Q = (3.55 x 10-10 F) * (9.00 V)
The charge it holds is thus approximately 3.20 x 10-9 C.