Question

Calculate the voltage applied to a (2.00 , mu F) capacitor when it holds (3.10 , mu C) of charge.

a) (1.55 , V)
b) (6.20 , V)
c) (0.65 , V)
d) (3.10 , V)

Answer 1

The voltage applied to a 2.00 µF capacitor holding 3.10 µC of charge can be calculated using the formula V = Q / C, resulting in a voltage of 1.55 V.

Step-by-step explanation:

To calculate the voltage applied to a capacitor, we can use the formula:

V = Q / C

where V is the voltage, Q is the charge, and C is the capacitance. In this case, we need to find the voltage V for a capacitor with a charge Q of 3.10 µC and a capacitance C of 2.00 µF.

Step-by-step calculation:

1. Convert the charge and the capacitance to common units if necessary. Here, they are already in microCoulombs (µC) and microFarads (µF), so we can proceed directly.
2. Plug the given values into the formula:

V = 3.10 µC / 2.00 µF

V = 1.55 V

Therefore, the voltage applied to a 2.00 µF capacitor when it holds 3.10 µC of charge is 1.55 volts (V).