Final answer:
The ratio of intensities of two sounds with identical frequency, where the first sound is just barely discernible as louder to a person than the second, is approximately 2.00.
Step-by-step explanation:
The ratio of intensities of two sounds with identical frequency, where the first sound is just barely discernible as louder than the second, is given by the formula I_1/I_2 = 10^(ΔL/10), where ΔL is the difference in sound intensity levels.
The ratio of intensities of two sounds with identical frequency, where the first sound is just barely discernible as louder to a person than the second, is approximately 2.00.
In this case, if the first sound is just barely discernible as louder to a person than the second, the ΔL is approximately 3 dB. Therefore, the ratio of intensities is I_1/I_2 ≈ 10^(3/10) ≈ 1.995.
So, the correct option is (a) (I_1/I_2 = 2.00).