Question

Find the sound intensity level in decibels of (2.00 X 10^2 W/m^2) ultrasound used in medical diagnostics.

a) 10 dB
b) 13 dB
c) 20 dB
d) 26 dB

Answer 1

The sound intensity level of the given ultrasound is 100 dB.

Step-by-step explanation:

The sound intensity level in decibels of 2.00 × 10-2 W/m² ultrasound used in medical diagnostics can be calculated using the formula:

β = 10 log10(I/I0)

where β is the sound intensity level in decibels, I is the given intensity (2.00 × 10-2 W/m²), and I0 is the reference intensity (10-12 W/m²).

Plugging in the values:

β = 10 log10((2.00 × 10-2) / (10-12))

β = 10 log10(2.00 × 1010)

β = 10 * 10 = 100 dB

Therefore, the sound intensity level in decibels of the given ultrasound is 100 dB.