Final answer:
Using equal-loudness contours and the relationship between decibels and intensity, we can determine the intensity of a 60.0 Hz sound with 60 phons loudness in watts per meter squared.
Step-by-step explanation:
The question concerns finding the intensity in watts per meter squared (W/m²) of sounds at different frequencies measured in phons, which is a unit of perceived loudness. Specifically, this question asks for a sound of 60.0 Hz with a loudness of 60 phons. The intensity level (in decibels) and intensity (in W/m²) corresponding to a specific loudness can be determined using standardized equal-loudness curves that show the relationship between loudness (phons), intensity level (decibels), and intensity (W/m²). These curves are particularly established for a frequency of 1000 Hz, where the phon and decibel values are equivalent.
For a sound at 60 phons and 60.0 Hz, we refer to the equal-loudness curves to find the corresponding intensity level in decibels (dB) and then use the formula for converting dB to intensity (W/m²). The relationship is typically the threshold of hearing at 0 dB is equivalent to an intensity of 1.0 × 10-12 W/m². Knowing the threshold, a formula is applied to calculate the requested intensities at both 60.0 Hz and 10,000 Hz frequencies for 60 phons. Please note that these calculations require previous knowledge on how to read an equal-loudness chart and apply the formula for sound intensity.