Question

If the spring has a force constant of 10.0 N/m and a 0.25-kg-mass object is set in motion as described, find the amplitude of the oscillations.

a) 0.10 m
b) 0.20 m
c) 0.25 m
d) 0.50 m

Answer 1

The amplitude of the oscillations is 0.50 m.

Step-by-step explanation:

To find the amplitude of the oscillations, we can use the equation for the period of a mass-spring system: T = 2π√(m/k), where T is the period, m is the mass, and k is the force constant of the spring. Rearranging the equation, we get: A = (m/k)^(1/2), where A is the amplitude.

Plugging in the given values, the amplitude of the oscillations is: A = (0.25 kg)/(10.0 N/m)^(1/2) = 0.50 m.

Therefore, the correct answer is d) 0.50 m.