Final answer:
The frequency of the radio waves from the Voyager spacecraft with a wavelength of 0.120 m and speed of 3.00 \(\times 10^8 m/s is 2.50 \(\times 10^8 Hz.
Step-by-step explanation:
The frequency of radio waves transmitted by the Voyager spacecraft through space can be calculated using the formula for wave speed v = f \(\lambda, where v is the wave speed, f is the frequency, and \(\lambda is the wavelength. Given that the wave speed v is 3.00 \(\times 10^8 m/s (the speed of light) and the wavelength \(\lambda is 0.120 m, you can rearrange the formula to solve for frequency: f = v / \(\lambda. Therefore, the frequency f is calculated as 2.50 \(\times 10^8 Hz.
To find the frequency, divide the speed of light (3.00 \(\times 10^8 m/s) by the wavelength given (0.120 m), resulting in a frequency of 2.50 \(\times 10^8 Hz, which is option a).
To find the frequency of the radio waves transmitted by the Voyager spacecraft, we can use the equation:
speed of light = wavelength * frequency
Given that the speed of light is 3.00 * 10^8 m/s and the wavelength is 0.120 m, we can rearrange the equation to solve for frequency:
frequency = speed of light / wavelength
Plugging in the values, we get:
frequency = (3.00 * 10^8 m/s) / (0.120 m) = 2.50 * 10^8 Hz
Therefore, the frequency of the radio waves transmitted by the Voyager spacecraft is 2.50 * 10^8 Hz.