Question

In an air conditioner, 12.65 MJ of heat transfer occurs from a cold environment in 1.00 h.

(a) What mass of ice melting would involve the same heat transfer?

a) 500 kg
b) 1000 kg
c) 1500 kg
d) 2000 kg

Answer 1

The mass of ice that would melt with the same heat transfer of 12.65 MJ from an air conditioner is approximately 37.874 kg, which does not match any of the options provided in the multiple-choice question.

Step-by-step explanation:

To answer the question regarding the mass of ice melting that would involve the same heat transfer as in an air conditioner, we use the equation Q = mLf, where Q is the heat transfer, m is the mass of ice, and Lf is the latent heat of fusion of ice. Given that the latent heat of fusion of ice is 334 kJ/kg, and the heat transfer is 12.65 MJ (or 12,650 kJ), we can solve for m to find the mass of ice that would melt with the same heat transfer:

Q = mLf
12,650 kJ = m(334 kJ/kg)
m = 12,650 kJ / 334 kJ/kg
m = 37.874 kg

However, this mass does not match any of the options provided (a) 500 kg, (b) 1000 kg, (c) 1500 kg, or (d) 2000 kg. It appears there might be a misunderstanding or error in the question since the calculated mass is much less than any of the answer choices.