Question

Calculate the rate of heat conduction through house walls that are 13.0 cm thick and have an average thermal conductivity twice that of glass wool. Assume there are no windows or doors. The surface area of the walls is 120 m², and their inside surface is at 18.0ºC, while their outside surface is at 5.00ºC.

a) 2,400 W
b) 3,600 W
c) 4,800 W
d) 6,000 W

Answer 1

The rate of heat conduction through the house walls is 3,600 W.

Step-by-step explanation:

To calculate the rate of heat conduction through a house wall, we can use the formula:

Rate of heat conduction = (Thermal conductivity x Surface area x Temperature difference) / Thickness

Given that the thickness of the wall is 13.0 cm and the thermal conductivity is twice that of glass wool, we can multiply the thermal conductivity of glass wool by 2. The surface area of the walls is 120 m², and the temperature difference is the difference between the inside surface temperature of 18.0°C and the outside surface temperature of 5.00°C.

Plugging in these values into the formula, we get a rate of heat conduction of 3,600 W.

Therefore, the correct answer is (b) 3,600 W.