Question

What is the efficiency of a cyclical heat engine with 2.56 × 10⁶ J of heat transfer into the engine and can do only 1.50 × 10⁵ J of work?

a) 5.86%
b) 6.12%
c) 6.45%
d) 6.78%

Answer 1

The efficiency of the cyclical heat engine is 5.86%.

Step-by-step explanation:

To find the efficiency of the cyclical heat engine, we can use the formula:

Efficiency = (Useful work output / Heat input)

Given that the heat transfer into the engine is 2.56 × 10⁶ J and the work done by the engine is 1.50 × 10⁵ J, we can plug in these values into the formula:

Efficiency = (1.50 × 10⁵ J / 2.56 × 10⁶ J)

Efficiency ≈ 0.0586 or 5.86%

The efficiency of the cyclical heat engine is 5.86%.