Question

A helium-filled rigid ball has a gauge pressure of 0.200 atm and a volume of 10.0 L. How much greater is the internal energy of the helium in the ball than it would be at zero gauge pressure?

a) 0.83 kJ
b) 1.66 kJ
c) 2.49 kJ
d) 3.32 kJ

Answer 1

The internal energy of the helium in the ball is 0.200 times greater than it would be at zero gauge pressure.

Step-by-step explanation:

The internal energy of a gas is given by the equation U = nKT, where U is the internal energy, n is the number of moles of gas, K is the Boltzmann constant, and T is the temperature. In this problem, we need to compare the internal energy of helium in the ball at a gauge pressure of 0.200 atm to the internal energy at zero gauge pressure.

The internal energy is directly proportional to the pressure of the gas. Since the gauge pressure is 0.200 atm, the difference in internal energy would be 0.200 times the original internal energy at zero gauge pressure.

Therefore, the internal energy of the helium in the ball is 0.200 times greater than it would be at zero gauge pressure.