Question

What is the mass of the solute in 0.500 L of 0.30 M glucose, C₆H₁2O₆, used for intravenous injection?

a) 27 g
b) 45 g
c) 54 g
d) 90 g

Answer 1

The mass of the solute in 0.500 L of 0.30 M glucose solution is calculated to be 27 grams by first finding the moles of glucose (0.500 L × 0.30 mol/L = 0.150 mol) and then multiplying by the molar mass of glucose (0.150 mol × 180.16 g/mol = 27.024 g).

Step-by-step explanation:

To calculate the mass of the solute in a 0.500 L of 0.30 M glucose solution, we follow a two-step process:

First, calculate the number of moles of glucose by multiplying the volume of the solution (in liters) by the molarity (M).

Then calculate the mass of glucose by multiplying the number of moles by the molar mass of glucose (C6H12O6), which is 180.16 g/mol.

We know that:

Moles of glucose = 0.500 L × 0.30 mol/L = 0.150 mol

Mass of glucose = 0.150 mol × 180.16 g/mol = 27.024 g

Therefore, the mass of glucose dissolved is 27 g. The correct answer would be (a) 27 g.