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How much heat transfer is required to raise the temperature of a 0.750-kg aluminum pot containing 2.50 kg of water from 30.0ºC to the boiling point and then boil away 0.750 kg of water?

a) 22,300 J
b) 125,000 J
c) 418,000 J
d) 837,000 J

User Shireen
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1 Answer

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Final answer:

To calculate the heat transfer required to raise the temperature of the aluminum pot and water, calculate the heat transfer required to raise the temperature of the water and the heat transfer required to boil the water away. The total heat transfer required is the sum of these two values.

Step-by-step explanation:

To calculate the heat transfer required to raise the temperature of the aluminum pot and water, we need to consider two steps: heating the water and boiling it away. First, we calculate the heat transfer required to raise the temperature of the water from 30.0°C to the boiling point using the specific heat capacity of water (4186 J/kg°C) and the mass of water (2.50 kg). This gives us a heat transfer of Q₁.

Next, we calculate the heat transfer required to boil away the 0.750 kg of water using the latent heat of vaporization of water (2257 kJ/kg) and the mass of water boiled away (0.750 kg). This gives us a heat transfer of Q₂. Finally, the total heat transfer required is the sum of Q₁ and Q₂.

From the given options, the correct answer is (c) 418,000 J.

User Mayur Sojitra
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