Question

What was the heat transfer into a heat engine that does 10.0 kJ of work and has 8.50 kJ of heat transfer to the environment in a cyclical process?

a) 18.5 kJ
b) 19.0 kJ
c) 19.5 kJ
d) 20.0 kJ

Answer 1

The heat transfer into the heat engine is 18.5 kJ, calculated by adding the work done by the engine (10.0 kJ) to the heat expelled to the environment (8.50 kJ).

Step-by-step explanation:

The question pertains to calculating the heat transfer into a heat engine that operates in a cyclical process. According to the first law of thermodynamics, the heat added to the system (Qin) is equal to the work done by the system (W) plus the heat expelled to the environment (Qout).

Using the provided values, where W is 10.0 kJ and Qout is 8.50 kJ, the heat transfer into the engine (Qin) can be calculated as follows:

Qin = W + QoutQin = 10.0 kJ + 8.50 kJ
Qin = 18.5 kJ

Therefore, the heat transfer into the heat engine is 18.5 kJ, which corresponds to option (a).