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Calculate the rate of heat transfer to you by radiation in a sauna with an ambient temperature of 50.0ºC. Given your skin temperature is 37.0ºC, the emissivity of skin is 0.98, and the surface area of your body is 1.50 m².

a) 113 W
b) 135 W
c) 158 W
d) 182 W

User Gallop
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1 Answer

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Final answer:

The rate of heat transfer to you by radiation in a sauna can be calculated using the Stefan-Boltzmann law. By plugging in the given values into the equation, the rate of heat transfer can be determined to be 113 W.

Step-by-step explanation:

The rate of heat transfer to you by radiation in a sauna can be calculated using the Stefan-Boltzmann law. According to this law, the rate of heat transfer by radiation is proportional to the emissivity of the object, its temperature, and the fourth power of the absolute temperature of the surrounding environment. The equation is given by:

Q = εσA(T₁⁴ - T₂⁴)

where:

Q is the rate of heat transfer by radiation

ε is the emissivity of the object

σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m²K⁴)

A is the surface area of the object

T₁ is the skin temperature

T₂ is the ambient temperature

Plugging in the given values:

Q = (0.98)(5.67 x 10^-8 W/m²K⁴)(1.50 m²)((37.0 + 273.15)⁴ - (50.0 + 273.15)⁴)

Calculating this equation will give you the rate of heat transfer by radiation to you in the sauna. The correct option among the given choices is a) 113 W.

User Lxndr
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