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The same heat transfer into identical masses of different substances produces different temperature changes. Calculate the final temperature when 1.00 kcal of heat transfers into 1.00 kg of the following, originally at 20.0ºC:

(a) water;
(b) concrete;
(c) steel; and
(d) mercury.

a) (a) 25.0ºC, (b) 22.8ºC, (c) 21.2ºC, (d) 18.5ºC
b) (a) 30.0ºC, (b) 25.5ºC, (c) 23.0ºC, (d) 20.5ºC
c) (a) 32.5ºC, (b) 28.0ºC, (c) 25.2ºC, (d) 22.0ºC
d) (a) 35.0ºC, (b) 31.2ºC, (c) 28.5ºC, (d) 25.0ºC

1 Answer

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Final answer:

The final temperature when 1.00 kcal of heat is transferred to 1.00 kg of different substances initially at 20.0°C can be calculated using the formula ΔT = Q / (m*c). Specific heat capacities of the substances are required to determine the temperature change and thus the final temperature.

Step-by-step explanation:

The calculation of the final temperature when heat transfer is applied to different substances is a basic concept in thermodynamics, in the field of Physics. When 1.00 kcal (or 4184 Joules) of heat is transferred into 1.00 kg of a substance that is initially at 20.0°C, the change in temperature can be calculated using the specific heat capacity of the substance.

The specific heat capacity is a property that indicates how much heat energy is required to raise the temperature of a certain mass of a substance by one degree Celsius.

The formula to find the change in temperature is given by ΔT = Q / (m*c), where ΔT is the change in temperature, Q is the heat added, m is the mass of the substance, and c is the specific heat capacity of the substance. For each substance, we know m = 1.00 kg and Q = 1.00 kcal (4184 J), but we need to use the specific heat capacity (c) for water, concrete, steel, and mercury to find the final temperatures.

Using the known values of c for each substance, you will calculate ΔT for each and add this to the original temperature to find the final temperatures.

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