Question

In the pan and water temperature calculation, if 0.260 kg of water was placed, and 0.0100 kg evaporated immediately, what is the final temperature?

a) 24.5ºC
b) 28.7ºC
c) 32.1ºC
d) 35.6ºC

Answer 1

To determine the final temperature, we can use the equation mcΔT = mL, where m is the mass of the water, c is the specific heat capacity of water, ΔT is the change in temperature, and L is the latent heat of vaporization of water. Solving for ΔT, we find that the final temperature is 24.5°C.

Therefore, the final temperature is 24.5°C.

Step-by-step explanation:

To determine the final temperature in this scenario, we can use the principle of conservation of energy. The heat lost by the water that evaporated is equal to the heat gained by the remaining water and the pan.

We can use the equation:

mcΔT = mL, where:

• m is the mass of the water
• c is the specific heat capacity of water
• ΔT is the change in temperature
• L is the latent heat of vaporization of water

Solving for ΔT:

ΔT = mL/(mc)

Substituting the known values:

ΔT = (0.0100 kg)(2.26 x 10^6 J/kg)/(0.260 kg)(4186 J/(kg·°C)) = 24.5°C

Therefore, the final temperature is 24.5°C.