Question

What volume of a 0.20-M K₂SO₄ solution contains 57 g of K₂SO₄?

a) 1.42 L
b) 0.71 L
c) 2.84 L
d) 5.68 L

Answer 1

To find the volume of a 0.20-M K2SO4 solution that contains 57 g of K2SO4, start by determining the number of moles of K2SO4, then divide by the molarity. However, the computed volume of 1.635 L is not listed among the provided options.

Step-by-step explanation:

To calculate the volume of a 0.20-M K2SO4 solution that contains 57 g of K2SO4, use the formula:

Volume (L) = moles of solute / molarity (M)

First, calculate the moles of K2SO4 by dividing the mass of the solute (given in grams) by its molar mass:

Molar mass of K2SO4 = 2(K) + S + 4(O) = 2(39.10) + 32.07 + 4(16.00) = 174.27 g/mol

Moles of K2SO4 = 57 g / 174.27 g/mol = 0.327 moles

Then, use the given molarity to find the volume:

Volume (L) = 0.327 moles / 0.20 M = 1.635 L

So, the correct answer is not listed among the options given, and we should report this finding accordingly.