Question

What is the molarity of HCl if 35.23 mL of a solution of HCl contains 0.3366 g of HCl?

a) 0.50 M
b) 1.00 M
c) 1.50 M
d) 2.00 M

Answer 1

The molarity of an HCl solution is calculated by converting the mass of HCl to moles, changing the volume of the solution to liters, and then dividing moles by volume. The computed molarity is approximately 0.262 M, which is not given in the options provided in the question.

Step-by-step explanation:

To determine the molarity of an HCl solution, one must first understand that molarity is defined as moles of solute per liter of solution. The steps necessary to calculate the molarity of HCl in this case are as follows:

1. Convert the mass of HCl to moles using the molar mass of HCl (36.461 g/mol).
2. Convert the volume of the solution from milliliters to liters.
3. Calculate the molarity by dividing the number of moles of HCl by the volume of the solution in liters.

Answer:

• Moles of HCl = mass of HCl (g) / molar mass of HCl (g/mol)
• Moles of HCl = 0.3366 g / 36.461 g/mol = 0.00923 mol (rounded to 5 significant figures)
• Volume in liters = 35.23 mL × (1 L / 1000 mL) = 0.03523 L
• Molarity = moles of HCl / volume of solution (L) = 0.00923 mol / 0.03523 L = 0.262 M (rounded to three significant figures)

Thus, the correct answer is not given in the provided options (a - 0.50 M, b - 1.00 M, c - 1.50 M, d - 2.00 M). The molarity of HCl in this scenario is approximately 0.262 M.