Final answer:
The molar concentration of Ca²⁺ ions in a water sample with a hardness count of 175 mg CaCO₃/L is 0.001749 M. The correct option is (A).
Step-by-step explanation:
The molar concentration of Ca²⁺ ions in a water sample with a hardness count of 175 mg CaCO₃/L can be calculated as follows:
First, we need to convert the hardness count from mg CaCO₃/L to moles of CaCO₃/L.
Given that the molar mass of CaCO₃ is 100.09 g/mol, we can calculate:
175 mg CaCO₃/L * (1 g / 1000 mg) * (1 mol CaCO₃ / 100.09 g) = 0.001749 mol CaCO₃/L
Since the molar ratio between Ca²⁺ ions and CaCO₃ is 1:1, the molar concentration of Ca²⁺ ions is the same as the molar concentration of CaCO₃, which is 0.001749 M.