Question

What volume of a 0.33-M C₁₂H₂₂O₁₁ solution can be diluted to prepare 25 mL of a solution with a concentration of 0.025 M?

a) 0.0076 L
b) 0.303 L
c) 0.76 L
d) 7.6 L

Answer 1

To prepare 25 mL of a 0.025 M sucrose solution from a 0.33-M sucrose solution, approximately 1.9 mL of the concentrated solution is required.

Step-by-step explanation:

The question asks to find the volume of a 0.33-M C12H22O11 solution (sucrose) that can be diluted to prepare 25 mL of a 0.025 M solution. This is a dilution problem that can be solved using the dilution formula M1V1 = M2V2, where M1 and V1 are the molarity and volume of the initial solution, and M2 and V2 are the molarity and volume of the final solution.

Solving the equation (0.33 M)(V1) = (0.025 M)(25 mL), we can find the volume V1 required. Dividing both sides of the equation by 0.33 M, we get V1 = (0.025 M × 25 mL) / 0.33 M.

Therefore, the volume V1 needed is approximately 1.9 mL, and the closest answer option is 0.0076 L when converted to liters (since 1.9 mL is equal to 0.0019 L).