Question

Determine the molarity of each of the following solutions:

a) 0.25 M
b) 0.50 M
c) 0.75 M
d) 1.00 M

Answer 1

The molarity of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters. Example calculations show that 1.457 mol KCl in 1.500 L of solution has a molarity of 0.9713 M, and a 1.00 L of a 0.250-M solution of Fe(NO3)3 diluted to 2.00 L results in a molarity of 0.125 M.

Step-by-step explanation:

The molarity of a solution is defined as the number of moles of a solute divided by the volume of the solution in liters. To calculate the molarity, you can use the formula:

Molarity (M) = moles of solute / volume of solution in liters

Using this formula, you can determine the molarity of each solution provided. For instance:

1. (a) 1.457 mol KCl in 1.500 L of solution: To find the molarity, divide the moles of KCl by the volume of the solution. Molarity = 1.457 mol / 1.500 L = 0.9713 M.
2. (b) 1.00 L of a 0.250-M solution of Fe(NO3)3 is diluted to a final volume of 2.00 L. The molarity of the diluted solution can be found by applying the dilution formula M1V1=M2V2, where M1 and V1 are the molarity and volume of the initial solution, respectively, and M2 and V2 are the molarity and volume of the diluted solution. For this example, (0.250 M)(1.00 L) = (M2)(2.00 L), so M2 = 0.125 M.