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Ten grams of H₂O starts as ice at 0°C. The ice absorbs heat from the air (just above 0°C) until all of it melts. Calculate the entropy change of the H₂O, of the air, and of the universe.

Entropy change of H₂O
Entropy change of air
Entropy change of the universe
None of the above

User Diand
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1 Answer

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Final answer:

The entropy change of H₂O, air, and the universe can be calculated based on the heat absorbed and temperature. The entropy change of the H₂O can be calculated by dividing the heat of fusion by the temperature in Kelvin. The entropy change of the air is negligible, resulting in the entropy change of the universe being approximately equal to the entropy change of the H₂O.

Step-by-step explanation:

The entropy change of a system can be calculated using the formula ∈S = Q/T, where Q is the heat transferred and T is the temperature in Kelvin. In this case, the initial state of the system is ice at 0 °C and the final state is water at 0 °C. During the process of melting, the system absorbs heat from the air, so its entropy increases. The entropy change of the H₂O can be calculated by finding the heat absorbed, which is the heat of fusion, and dividing it by the temperature in Kelvin. The entropy change of the air can be considered negligible, as no phase change occurs. The entropy change of the universe can be calculated by adding the entropy changes of the H₂O and the air. Since the entropy change of the air is negligible, the entropy change of the universe is approximately equal to the entropy change of the H₂O.

User Siavash Alp
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