Answer:
There is significant evidence that Jane has met the requirement.
Explanation:
Given that:
μ = 100
μ > 100
Sample size, n = 16
Sample mean, x = 108
Sample standard deviation, s = 12
Level of significance, α = 0.1
Degree of freedom, df = n - 1 = 16 - 1 = 15
Test statistic
T = (x - μ) / s÷sqrt(n)
Tstatistic = (108 - 100) / 12 ÷ sqrt(16)
Tstatistic = 8 / 3
Tstatistic = 2.6667
Using the pvalue calculator :
Tstatistic at 0.1, df = 15 ;
P-value = 0.008799
Since pvalue < α
We reject the Null
The is no significant evidence to conclude that Jane has exceeded an average of more than $100