Question

Iodine forms a series of fluorides (listed here). Write Lewis structures for each of the four compounds and determine the formal charge of the iodine atom in each molecule:

a) +1, 0, -1, -2
b) 0, -1, -2, -3
c) +1, -1, -2, -3
d) 0, +1, -2, -3

Answer 1

The Lewis structures and formal charges for each of the four iodine fluorides compounds are: IF (+1), IF3 (0), IF5 (-1), and IF7 (-1).

Step-by-step explanation:

The Lewis structures and formal charges for each of the four compounds are as follows:

a) IF: The Lewis structure for IF is
I:F. The formal charge of the iodine atom in IF is +1.

b) IF3: The Lewis structure for IF3 is
F-I-F. The formal charge of the iodine atom in IF3 is 0.

c) IF5: The Lewis structure for IF5 is
F-I-F-F-F-F. The formal charge of the iodine atom in IF5 is -1.

d) IF7: The Lewis structure for IF7 is
F-I-F-F-F-F-F-F. The formal charge of the iodine atom in IF7 is -1.